a dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent…

a dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 percent brush at least twice a day and floss daily. what is the probability that a patient flosses daily, given that he or she brushes at least twice a day? round to the nearest percent.\n16%\n23%\n40%\n57%

a dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 percent brush at least twice a day and floss daily. what is the probability that a patient flosses daily, given that he or she brushes at least twice a day? round to the nearest percent.\n16%\n23%\n40%\n57%

Answer

Explanation:

Step1: Identify the formula

Use the formula for conditional probability $P(A|B)=\frac{P(A\cap B)}{P(B)}$. Let $A$ be the event of flossing daily and $B$ be the event of brushing at least twice a day.

Step2: Assign values

We know that $P(B) = 0.83$ (probability of brushing at least twice a day), and $P(A\cap B)=0.19$ (probability of brushing at least twice a day and flossing daily).

Step3: Calculate the conditional probability

$P(A|B)=\frac{0.19}{0.83}\approx 0.23$

Answer:

23%