a dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent…

a dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 percent brush at least twice a day and floss daily. what is the probability that a patient flosses daily, given that he or she brushes at least twice a day? round to the nearest percent.\no 16%\no 23%\no 40%\no 57%

a dentist polls his patients and finds that 83 percent brush their teeth at least twice a day, 47 percent floss daily, and 19 percent brush at least twice a day and floss daily. what is the probability that a patient flosses daily, given that he or she brushes at least twice a day? round to the nearest percent.\no 16%\no 23%\no 40%\no 57%

Answer

Explanation:

Step1: Recall conditional - probability formula

The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. Let $A$ be the event that a patient flosses daily and $B$ be the event that a patient brushes at least twice a day.

Step2: Identify the given probabilities

We are given that $P(B) = 0.83$ (probability of brushing at least twice a day), $P(A)=0.47$ (probability of flossing daily), and $P(A\cap B)=0.19$ (probability of brushing at least twice a day and flossing daily).

Step3: Calculate the conditional probability

Substitute the values into the formula: $P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0.19}{0.83}\approx0.23$.

Answer:

23%