determine whether this table represents a probability distribution.\n|x|p(x)|\n|0|0.2|\n|1|0.2|\n|2|0.2|\n|3|…

determine whether this table represents a probability distribution.\n|x|p(x)|\n|0|0.2|\n|1|0.2|\n|2|0.2|\n|3|0.4|\nno, it is not a probability distribution\nyes, it is a probability distribution

determine whether this table represents a probability distribution.\n|x|p(x)|\n|0|0.2|\n|1|0.2|\n|2|0.2|\n|3|0.4|\nno, it is not a probability distribution\nyes, it is a probability distribution

Answer

Explanation:

Step1: Check probability range

All $P(x)$ values ($0.2, 0.2, 0.2, 0.4$) are between $0$ and $1$.

Step2: Sum of probabilities

Calculate $\sum_{i}P(x_i)=0.2 + 0.2+0.2 + 0.4$. $0.2 + 0.2+0.2 + 0.4=1$. Since all probabilities are between $0$ and $1$ and their sum is $1$, it meets the criteria for a probability - distribution.

Answer:

Yes, it is a probability distribution