9 a die is rolled 4 times. what is the chance that none of the rolls show 4 or more spots?\na. less than…

9 a die is rolled 4 times. what is the chance that none of the rolls show 4 or more spots?\na. less than 1%\nb. 1.20%\nc. 6.25%\nd. 50%\ne. 93.75%
Answer
Explanation:
Step1: Calculate single - roll probability
A standard die has 6 faces. The numbers less than 4 are 1, 2, 3. So the probability of getting a number less than 4 in a single roll is $p=\frac{3}{6}=\frac{1}{2}$.
Step2: Use independent - event formula
Since the rolls of the die are independent events, the probability of getting a number less than 4 in all 4 rolls is $P = (\frac{1}{2})\times(\frac{1}{2})\times(\frac{1}{2})\times(\frac{1}{2})=\left(\frac{1}{2}\right)^4$.
Step3: Calculate the final probability
$\left(\frac{1}{2}\right)^4=\frac{1}{16}= 0.0625 = 6.25%$.
Answer:
C. 6.25%