directions: solve the following problems by finding the median, interquartile range (iqr), or range. you may…

directions: solve the following problems by finding the median, interquartile range (iqr), or range. you may use a calculator, but you must show your work! 1. {13, 15, 9, 35, 25} median = ____ q1 = ____ q3 = ____ iqr = ____ 2. {6, 1, 3, 8, 5, 11, 1, 5} median = ____ q1 = ____ q3 = ____ iqr = ____
Answer
Explanation:
Step1: Sort the data set {13, 15, 9, 35, 25}
{9, 13, 15, 25, 35}
Step2: Find the median
Since there are 5 data - points (n = 5), the median is the $\left(\frac{n + 1}{2}\right)$-th value. $\frac{5+1}{2}=3$ - rd value, so Median = 15.
Step3: Find Q1 and Q3
The lower half of the data set is {9, 13}, and the upper half is {25, 35}. For the lower half (n = 2), the median of the lower half (Q1) is $\frac{9 + 13}{2}=11$. For the upper half (n = 2), the median of the upper half (Q3) is $\frac{25+35}{2}=30$.
Step4: Calculate the IQR
IQR=Q3 - Q1, so IQR = 30 - 11=19.
Step5: Sort the data set {6, 1, 3, 8, 5, 11, 1, 5}
{1, 1, 3, 5, 5, 6, 8, 11}
Step6: Find the median
Since there are 8 data - points (n = 8), the median is the average of the $\frac{n}{2}$-th and $\left(\frac{n}{2}+1\right)$-th values. $\frac{8}{2}=4$ and $\frac{8}{2}+1 = 5$. Median=$\frac{5 + 5}{2}=5$.
Step7: Find Q1 and Q3
The lower half of the data set is {1, 1, 3, 5}, and the upper half is {5, 6, 8, 11}. For the lower half (n = 4), the median of the lower half (Q1) is $\frac{1+3}{2}=2$. For the upper half (n = 4), the median of the upper half (Q3) is $\frac{6 + 8}{2}=7$.
Step8: Calculate the IQR
IQR=Q3 - Q1, so IQR = 7 - 2=5.
Answer:
- Median = 15 Q1 = 11 Q3 = 30 IQR = 19
- Median = 5 Q1 = 2 Q3 = 7 IQR = 5