drag the tiles to the boxes to form correct pairs. match the values associated with this data set to their…

drag the tiles to the boxes to form correct pairs. match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45

drag the tiles to the boxes to form correct pairs. match the values associated with this data set to their correct descriptions. {6, 47, 49, 15, 43, 41, 7, 36} first quartile 38.5 median 11 third quartile 10.5 the difference of the largest value and the median 45

Answer

Explanation:

Step1: Sort the data - set

Sort the data set ${6,47,49,15,43,41,7,36}$ in ascending - order: ${6,7,15,36,41,43,47,49}$.

Step2: Calculate the median

Since there are $n = 8$ data points, the median is the average of the $\frac{n}{2}$ - th and $(\frac{n}{2}+1)$ - th ordered values. The $\frac{8}{2}=4$ - th value is $36$ and the $(\frac{8}{2}+1)=5$ - th value is $41$. Median $=\frac{36 + 41}{2}=38.5$.

Step3: Calculate the first quartile

The lower half of the data set is ${6,7,15,36}$. Since there are $n_1 = 4$ data points in the lower half, the first quartile $Q_1$ is the average of the $\frac{n_1}{2}$ - th and $(\frac{n_1}{2}+1)$ - th ordered values in the lower half. The $\frac{4}{2}=2$ - th value is $7$ and the $(\frac{4}{2}+1)=3$ - th value is $15$. $Q_1=\frac{7 + 15}{2}=11$.

Step4: Calculate the third quartile

The upper half of the data set is ${41,43,47,49}$. Since there are $n_2 = 4$ data points in the upper half, the third quartile $Q_3$ is the average of the $\frac{n_2}{2}$ - th and $(\frac{n_2}{2}+1)$ - th ordered values in the upper half. The $\frac{4}{2}=2$ - th value is $43$ and the $(\frac{4}{2}+1)=3$ - th value is $47$. $Q_3=\frac{43+47}{2}=45$.

Step5: Calculate the difference of the largest value and the median

The largest value is $49$ and the median is $38.5$. The difference is $49 - 38.5 = 10.5$.

Answer:

First quartile $\leftrightarrow11$ $38.5\leftrightarrow$ median $11\leftrightarrow$ first quartile Third quartile $\leftrightarrow45$ $10.5\leftrightarrow$ the difference of the largest value and the median