edwards class collected signatures for a petition. by the end, 6 students had collected: 84 signatures 71…

edwards class collected signatures for a petition. by the end, 6 students had collected: 84 signatures 71 signatures 98 signatures 50 signatures 96 signatures 99 signatures what was the mean absolute deviation of the numbers of signatures collected? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): signatures

edwards class collected signatures for a petition. by the end, 6 students had collected: 84 signatures 71 signatures 98 signatures 50 signatures 96 signatures 99 signatures what was the mean absolute deviation of the numbers of signatures collected? if the answer is a decimal, round it to the nearest tenth. mean absolute deviation (mad): signatures

Answer

Explanation:

Step1: Calculate the mean

The data set is (84, 71, 98, 50, 96, 99). The mean (\bar{x}=\frac{84 + 71+98+50+96+99}{6}=\frac{498}{6}=83).

Step2: Calculate the absolute - deviations

(\vert84 - 83\vert=1), (\vert71 - 83\vert = 12), (\vert98 - 83\vert=15), (\vert50 - 83\vert = 33), (\vert96 - 83\vert=13), (\vert99 - 83\vert=16).

Step3: Calculate the mean of the absolute - deviations

The mean absolute deviation (MAD=\frac{1+12 + 15+33+13+16}{6}=\frac{90}{6}=15.0).

Answer:

15.0