what effect does eliminating the highest value, 180, from the data set have on the mean and median?\n25 50…

what effect does eliminating the highest value, 180, from the data set have on the mean and median?\n25 50 50 60 70 85 85 90 90 180

what effect does eliminating the highest value, 180, from the data set have on the mean and median?\n25 50 50 60 70 85 85 90 90 180

Answer

Explanation:

Step1: Calculate the original mean

The formula for the mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. Here $n = 10$, and $\sum_{i=1}^{10}x_{i}=25 + 50+50 + 60+70+85+85+90+90+180=785$. So the original mean $\bar{x}_1=\frac{785}{10}=78.5$.

Step2: Calculate the original median

Since $n = 10$ (an even - numbered data set), the median is the average of the $\frac{n}{2}$th and $(\frac{n}{2}+1)$th ordered values. The ordered data set is $25,50,50,60,70,85,85,90,90,180$. The $\frac{n}{2}=5$th value is $70$ and the $(\frac{n}{2}+1)=6$th value is $85$. So the original median $M_1=\frac{70 + 85}{2}=77.5$.

Step3: Calculate the new mean after eliminating 180

Now $n = 9$, and $\sum_{i = 1}^{9}x_{i}=785-180 = 605$. So the new mean $\bar{x}_2=\frac{605}{9}\approx67.22$.

Step4: Calculate the new median after eliminating 180

The new ordered data set is $25,50,50,60,70,85,85,90,90$. Since $n = 9$ (an odd - numbered data set), the median is the $(\frac{n + 1}{2})$th value. $\frac{n+1}{2}=5$th value, so the new median $M_2 = 70$.

Step5: Analyze the changes

The mean changes from $78.5$ to approximately $67.22$, so the mean decreases. The median changes from $77.5$ to $70$, so the median decreases.

Answer:

The mean and median both decrease.