elena lists the ages of all of the family members who live in her house below. what is the mean absolute…

elena lists the ages of all of the family members who live in her house below. what is the mean absolute deviation (mad) of their ages? 9, 13, 43, 55

elena lists the ages of all of the family members who live in her house below. what is the mean absolute deviation (mad) of their ages? 9, 13, 43, 55

Answer

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{9 + 13+43+55}{4}=\frac{120}{4}=30$.

Step2: Calculate the absolute - deviations

$|9 - 30|=21$, $|13 - 30| = 17$, $|43 - 30|=13$, $|55 - 30| = 25$.

Step3: Calculate the mean of the absolute - deviations

$MAD=\frac{21+17+13+25}{4}=\frac{76}{4}=19$.

Answer:

19