the equation for the line of best fit is f(x) ≈ 1.8x - 5.4 for the set of values in the table. using the…

the equation for the line of best fit is f(x) ≈ 1.8x - 5.4 for the set of values in the table. using the equation for the line of best fit, what is a good approximation for x when f(x) = 30?\n\n| x | f(x) |\n|----|----|\n| 4 | 5 |\n| 5 | 2 |\n| 6 | 5 |\n| 6 | 6 |\n| 8 | 8 |\n| 9 | 7 |\n| 10 | 18 |\n\n14\n20\n45\n54

the equation for the line of best fit is f(x) ≈ 1.8x - 5.4 for the set of values in the table. using the equation for the line of best fit, what is a good approximation for x when f(x) = 30?\n\n| x | f(x) |\n|----|----|\n| 4 | 5 |\n| 5 | 2 |\n| 6 | 5 |\n| 6 | 6 |\n| 8 | 8 |\n| 9 | 7 |\n| 10 | 18 |\n\n14\n20\n45\n54

Answer

Explanation:

Step1: Substitute f(x) value

Given $f(x)=1.8x - 5.4$ and $f(x) = 30$, we substitute $f(x)$ in the equation: $30=1.8x - 5.4$.

Step2: Isolate the term with x

Add 5.4 to both sides of the equation: $30 + 5.4=1.8x$, so $35.4 = 1.8x$.

Step3: Solve for x

Divide both sides by 1.8: $x=\frac{35.4}{1.8}\approx19.67$. The closest value to this in the options is 20.

Answer:

20