which is equivalent to p(z ≥ 1.06)?\np(z ≤ 1.06)\np(z ≥ -1.06)\n1 - p(z ≤ 1.06)\ndone

Answer:

1 - P(z ≤ 1.06)

Explanation:

Step1: Recall normal - distribution property

The total area under the standard normal curve is 1.

Step2: Define areas

Let (A = P(z\geq1.06)) and (B = P(z\leq1.06)).

Step3: Use the total - area relationship

Since (A + B=1), we can solve for (A). So (A = 1 - B), that is (P(z\geq1.06)=1 - P(z\leq1.06)).