evaluate.\n$_{3}c_{2}=square$\nsubmit

Explanation:

Step1: Recall combination formula

The combination formula is ${n}C{r}=\frac{n!}{r!(n - r)!}$, where $n = 3$ and $r=2$.

Step2: Calculate factorial values

$n!=n\times(n - 1)\times\cdots\times1$. So, $3! = 3\times2\times1=6$, $2! = 2\times1 = 2$, and $(3 - 2)!=1!=1$.

Step3: Substitute into formula

${3}C{2}=\frac{3!}{2!(3 - 2)!}=\frac{6}{2\times1}=3$.

Answer:

3