evaluate.\n$_{3}p_{2} = \\square$\nsubmit

evaluate.\n$_{3}p_{2} = \\square$\nsubmit

evaluate.\n$_{3}p_{2} = \\square$\nsubmit

Answer

Explanation:

Step1: Recall permutation formula

The permutation formula is $_nP_r = \frac{n!}{(n-r)!}$, where $n=3$, $r=2$.

Step2: Calculate factorials

$3! = 3\times2\times1=6$, $(3-2)! = 1! = 1$

Step3: Compute the ratio

$\frac{3!}{(3-2)!} = \frac{6}{1}$

Answer:

6