which event is least likely to occur?\nanswer\nrolling a number greater than or equal to 4 on a twelve…
which event is least likely to occur?\nanswer\nrolling a number greater than or equal to 4 on a twelve - sided die, numbered from 1 to 12.\nspinning a spinner divided into four equal - sized sections colored red/green/yellow/blue and landing on red or yellow.\nwinning a raffle that sold a total of 100 tickets, if you buy 44 tickets.\nreaching into a bag full of 5 strawberry chews and 55 cherry chews without looking and pulling out a strawberry chew.
Answer
Explanation:
Step1: Calculate probability of die - roll
The total number of outcomes when rolling a twelve - sided die is $n = 12$. The number of favorable outcomes (rolling a number greater than or equal to 4) is $m=12 - 3=9$. The probability $P_1=\frac{9}{12}=\frac{3}{4}=0.75$.
Step2: Calculate probability of spinner spin
The spinner has 4 equal - sized sections. The number of favorable outcomes (landing on red or yellow) is 2. The probability $P_2=\frac{2}{4}=\frac{1}{2}=0.5$.
Step3: Calculate probability of raffle win
The total number of tickets is 100 and the number of tickets bought is 44. The probability of winning the raffle $P_3=\frac{44}{100}=0.44$.
Step4: Calculate probability of pulling a strawberry chew
The total number of chews in the bag is $5 + 55=60$, and the number of strawberry chews is 5. The probability $P_4=\frac{5}{60}=\frac{1}{12}\approx0.083$.
Answer:
Reaching into a bag full of 5 strawberry chews and 55 cherry chews without looking and pulling out a strawberry chew.