which event has a theoretical probability of exactly $\frac{3}{4}$? select three options.\nnot picking a…

Answer:

• not picking a square
• picking a triangle
• picking a shape that has only straight edges

Explanation:

Step1: Count total shapes

There are 8 shapes in total.

Step2: Analyze each option

Option 1: not picking a square

There are 2 squares. So not - picking a square means picking from 6 non - square shapes. Probability = $\frac{6}{8}=\frac{3}{4}$.

Option 2: picking a square

There are 2 squares. Probability = $\frac{2}{8}=\frac{1}{4}$.

Option 3: picking a triangle

There are 6 triangles. Probability = $\frac{6}{8}=\frac{3}{4}$.

Option 4: picking a shape that has only straight edges

Triangles and squares have straight edges. There are 2 squares and 6 triangles, so 8 in total. Probability = $\frac{6 + 2}{8}=\frac{8}{8} = 1$.

Option 5: not picking a circle

There are 2 circles. So not - picking a circle means picking from 6 non - circle shapes. Probability = $\frac{6}{8}=\frac{3}{4}$.