in an experiment, college students were given either four quarters or a $1 bill and they could either keep…

in an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it on gum. the results are summarized in the table. complete parts (a) through (c) below.\n| |purchased gum|kept the money|\n|--|--|--|\n|students given four quarters|28|17|\n|students given a $1 bill|15|34|\n\na. find the probability of randomly selecting a student who spent the money, given that the student was given four quarters.\nthe probability is 0.622.\n(round to three decimal places as needed.)\nb. find the probability of randomly selecting a student who kept the money, given that the student was given four quarters.\nthe probability is \n(round to three decimal places as needed.)

in an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or spend it on gum. the results are summarized in the table. complete parts (a) through (c) below.\n| |purchased gum|kept the money|\n|--|--|--|\n|students given four quarters|28|17|\n|students given a $1 bill|15|34|\n\na. find the probability of randomly selecting a student who spent the money, given that the student was given four quarters.\nthe probability is 0.622.\n(round to three decimal places as needed.)\nb. find the probability of randomly selecting a student who kept the money, given that the student was given four quarters.\nthe probability is \n(round to three decimal places as needed.)

Answer

Explanation:

Step1: Identify relevant numbers

For students given four - quarters, number who kept money is 17, total number of students given four - quarters is (28 + 17=45).

Step2: Calculate probability

The probability formula for conditional probability (P(A|B)=\frac{n(A\cap B)}{n(B)}). Here, (A) is the event of keeping money and (B) is the event of being given four - quarters. So the probability (P=\frac{17}{45}\approx0.378).

Answer:

0.378