a fair spinner is shown. janelle spins the spinner arrow 150 times. match each outcome with the number of…

a fair spinner is shown. janelle spins the spinner arrow 150 times. match each outcome with the number of times janelle should expect it to occur. 25 times 50 times 75 times 100 times 125 times the letter c is spun. the letter a or e is spun. any letter that is not e is spun.

a fair spinner is shown. janelle spins the spinner arrow 150 times. match each outcome with the number of times janelle should expect it to occur. 25 times 50 times 75 times 100 times 125 times the letter c is spun. the letter a or e is spun. any letter that is not e is spun.

Answer

Answer:

  • The letter C is spun: 25 times
  • The letter A or E is spun: 50 times
  • Any letter that is not E is spun: 125 times

Explanation:

Step1: Determine the probability of each outcome.

The spinner has 6 equally likely sections (A, B, C, D, E, F). The probability of landing on any specific letter is $\frac{1}{6}$.

  • Probability of C: $P(C) = \frac{1}{6}$
  • Probability of A or E: There are 2 favorable outcomes (A, E). So, $P(A \text{ or } E) = \frac{2}{6} = \frac{1}{3}$
  • Probability of not E: There are 5 favorable outcomes (A, B, C, D, F). So, $P(\text{not } E) = \frac{5}{6}$

Step2: Calculate the expected number of occurrences for each outcome.

The total number of spins is 150. Expected occurrences = Probability of outcome $\times$ Total spins.

  • Expected times C is spun: $$ E(C) = P(C) \times 150 = \frac{1}{6} \times 150 = 25 \text{ times} $$
  • Expected times A or E is spun: $$ E(A \text{ or } E) = P(A \text{ or } E) \times 150 = \frac{1}{3} \times 150 = 50 \text{ times} $$
  • Expected times any letter that is not E is spun: $$ E(\text{not } E) = P(\text{not } E) \times 150 = \frac{5}{6} \times 150 = 5 \times 25 = 125 \text{ times} $$