in the fall, ms. bradford recorded the number of times each of her homeroom students got the school lunch…

in the fall, ms. bradford recorded the number of times each of her homeroom students got the school lunch. this histogram shows the data she collected. school lunches based on the histogram, which of these statements are true? the mean is probably lower than the median. half of the students got the school lunch between 20 and 29 times. the data is skewed left.

in the fall, ms. bradford recorded the number of times each of her homeroom students got the school lunch. this histogram shows the data she collected. school lunches based on the histogram, which of these statements are true? the mean is probably lower than the median. half of the students got the school lunch between 20 and 29 times. the data is skewed left.

Answer

Explanation:

Step1: Analyze the shape of the histogram

The histogram has a long - tail on the left side, so the data is skewed left. In a left - skewed distribution, the mean is pulled in the direction of the tail, so the mean is probably lower than the median.

Step2: Calculate the total number of students

The number of students in each interval: 0 - 9: 1, 10 - 19: 2, 20 - 29: 6, 30 - 39: 7, 40 - 49: 9. The total number of students is (1 + 2+6 + 7+9=25). The median is the 13th value. The first two intervals have (1 + 2 = 3) students, and the first three intervals have (1+2 + 6=9) students. So the median lies in the 30 - 39 interval, not in the 20 - 29 interval.

Answer:

The mean is probably lower than the median. The data is skewed left.