favorite fruits\nfruits | votes\napples | \ngrapes | \npears | \nstrawberries | \nbananas | \nwhat is the…

Answer

Explanation:

Step1: Count votes for each fruit

Apples: Count the tally marks. A "hash" (##) is 5, plus 2 extra: (5 + 2 = 7)? Wait, no, let's count the tally marks for Apples: The tally is (\cancel{####} I) (wait, the image shows Apples as (\cancel{####} I)? Wait, no, looking at the image: Apples has a tally of (\cancel{####}) (which is 5) plus two more? Wait, no, let's re-express:
Apples: Tally marks: Let's count. The first four with a cross (which is 5), then two more? Wait, no, the standard tally: each group of 5 is (\cancel{####}). Wait, the Apples tally: (\cancel{####}) (5) + two? Wait, no, maybe I misread. Let's list each:
Apples: Let's count the vertical lines and the cross. Wait, the Apples tally is: (\cancel{####}) (5) + two? Wait, no, the image shows Apples as (\cancel{####} I)? Wait, no, maybe:

Wait, let's do each fruit:

Apples: Tally marks: Let's count. The first four with a cross (total 5), then two more? Wait, no, the standard is 5 per cross. Wait, maybe:

Apples: Let's count the number of tally marks. Let's see: the first part is (\cancel{####}) (5), then two more? Wait, no, the image: Apples has a tally of (\cancel{####}) (5) + two? Wait, maybe I made a mistake. Wait, let's check again:

Wait, the user's image:

Apples: Tally: (\cancel{####}) (5) + two? Wait, no, the Apples tally is: (\cancel{####}) (5) + two? Wait, maybe:

Wait, let's count each fruit's votes:

Apples: Let's count the tally marks. The tally is: (\cancel{####}) (5) + two? Wait, no, the image shows Apples as (\cancel{####} I)? Wait, no, maybe:

Wait, perhaps:

Apples: Tally marks: 5 (from the cross) + 2 = 7? Wait, no, maybe:

Wait, let's do it properly:

Apples: The tally is: | | | | | (crossed, 5) + | | (two more) → total 7?
Grapes: Tally: | | | | (4? Wait, the Grapes tally is: | | | /? Wait, no, Grapes: | | | |? Wait, the image shows Grapes as | | | |? Wait, no, Grapes: | | | /? Wait, no, the Grapes tally is: three vertical and one diagonal? Wait, no, the Grapes tally is: | | | /? Wait, no, maybe:

Wait, let's look again:

Apples: Tally: (\cancel{####}) (5) + two → 7?
Grapes: Tally: | | | |? No, the Grapes tally is: | | | /? Wait, no, maybe Grapes has 4? Wait, no, the Grapes tally is three vertical and one diagonal? Wait, no, the standard tally: each vertical is 1, and a diagonal for the 5th. Wait, maybe Grapes has 4? Wait, no, the Grapes tally is: | | | /? Wait, no, perhaps:

Wait, maybe I should look at the Pears tally, which is two groups of 5 (each (\cancel{####})) → 10? Wait, Pears: tally is (\cancel{####}) (5) + (\cancel{####}) (5) → 10?

Wait, let's list:

Apples: Let's count the tally marks. Let's see: the first part is (\cancel{####}) (5) + two? Wait, no, the Apples tally is: (\cancel{####}) (5) + two? Wait, maybe:

Wait, the Pears tally: two groups of (\cancel{####}) → 10.

Strawberries: (\cancel{####}) (5) + one → 6?

Bananas: 4 (| | | |).

Wait, let's re-express:

Apples: Tally: Let's count the number of marks. The first group is 5 (crossed), then two more: total 7.
Grapes: Tally: 4 (| | | |? Or | | | /? Wait, maybe 4).
Pears: Tally: two groups of 5 (each (\cancel{####})) → 10.
Strawberries: Tally: (\cancel{####}) (5) + one → 6.
Bananas: Tally: 4 (| | | |).

Wait, now, the mode is the value that appears most frequently. So we need to find which fruit has the most votes.

So:

Apples: 7?
Grapes: 4?
Pears: 10?
Strawberries: 6?
Bananas: 4?

Wait, if Pears has 10 votes (two groups of 5), that's the highest. Wait, but let's confirm:

Wait, Pears' tally: (\cancel{####}) (5) + (\cancel{####}) (5) → 10.

Apples: 5 (crossed) + 2 → 7.

Strawberries: 5 (crossed) + 1 → 6.

Grapes: 4.

Bananas: 4.

So Pears has the most votes (10), so the mode is the fruit with the most votes, which is Pears. Wait, but let's confirm the tally counts:

Wait, maybe I made a mistake in Apples' count. Let's recheck Apples:

Apples' tally: The image shows Apples as (\cancel{####}) (5) + two? Wait, no, the Apples tally is: (\cancel{####}) (5) + two? Wait, maybe the Apples tally is 7, Grapes 4, Pears 10, Strawberries 6, Bananas 4. So Pears has 10 votes, which is the highest. Therefore, the mode (the most frequent value, i.e., the fruit with the most votes) is Pears.

Wait, but let's confirm:

Apples: Let's count the tally marks. The first part is (\cancel{####}) (5), then two more: 5 + 2 = 7.
Grapes: Tally: | | | |? No, the Grapes tally is | | | /? Wait, no, the Grapes tally is three vertical and one diagonal, which is 4 (since each diagonal is a fifth, but if it's not crossed, maybe 3 + 1 = 4? Wait, no, the standard tally: each group of 5 is (\cancel{####}). So if Grapes has three vertical and one diagonal, that's 4 (since it's not a full group of 5). So Grapes: 4.
Pears: Two groups of (\cancel{####}) → 5 + 5 = 10.
Strawberries: (\cancel{####}) (5) + one → 6.
Bananas: 4.

So the votes are:

Apples: 7
Grapes: 4
Pears: 10
Strawberries: 6
Bananas: 4

The mode is the value (fruit) with the highest frequency (most votes). So Pears has 10 votes, which is more than the others. Therefore, the mode is Pears.

Step2: Determine the mode

The mode is the value that appears most frequently. In this case, we are looking at the number of votes (frequency) for each fruit. The fruit with the highest number of votes is the mode. From the counts:

Apples: 7
Grapes: 4
Pears: 10
Strawberries: 6
Bananas: 4

Pears has the highest number of votes (10), so the mode is Pears.

Answer:

Pears