find the indicated probability. a survey revealed that 31% of people are entertained by reading books, 39%…

find the indicated probability. a survey revealed that 31% of people are entertained by reading books, 39% are entertained by watching tv, and 30% are entertained by both books and tv. what is the probability that a person will be entertained by either books or tv? 0.40 0.70 0.30 0.22 1

find the indicated probability. a survey revealed that 31% of people are entertained by reading books, 39% are entertained by watching tv, and 30% are entertained by both books and tv. what is the probability that a person will be entertained by either books or tv? 0.40 0.70 0.30 0.22 1

Answer

Explanation:

Step1: Recall the formula for the probability of the union of two events

The formula for (P(A\cup B)) is (P(A)+P(B)-P(A\cap B)), where (A) is the event of being entertained by books and (B) is the event of being entertained by TV. Let (P(A) = 0.31), (P(B)=0.39) and (P(A\cap B)=0.30).

Step2: Substitute the values into the formula

(P(A\cup B)=0.31 + 0.39- 0.30) (P(A\cup B)=0.40)

Answer:

0.40