find p(c|y) from the information in the table. to the nearest tenth, what is the value of p(c|y)?\n| | x | y…

Explanation:

Step1: Recall conditional - probability formula

The formula for conditional probability is $P(C|Y)=\frac{P(C\cap Y)}{P(Y)}$. In terms of frequency, $P(C|Y)=\frac{n(C\cap Y)}{n(Y)}$, where $n(C\cap Y)$ is the number of elements in the intersection of $C$ and $Y$, and $n(Y)$ is the number of elements in $Y$.

Step2: Identify $n(C\cap Y)$ and $n(Y)$ from the table

From the table, $n(C\cap Y) = 15$ (the value in the cell where row $C$ and column $Y$ intersect), and $n(Y)=30$ (the total value in column $Y$).

Step3: Calculate $P(C|Y)$

$P(C|Y)=\frac{n(C\cap Y)}{n(Y)}=\frac{15}{30}=0.5$

Answer:

0.5