find the mean, median, mode and range for each set of data. calculator usage is encouraged! 1. 23, 87, 19…

find the mean, median, mode and range for each set of data. calculator usage is encouraged! 1. 23, 87, 19, 34, 37, 87, 81, 5, 14, 100, 26 2. 10, 11, 17, 14, 2, 13, 26 3. 86, 86, 24, 92, 37, 14, 52, 24, 63 4. 27, 54, 6, 31, 57, 22, 19, 12 5. 8, 32, 41, 6, 36, 10, 37, 31, 29, 37, 32, 11, 30, 15, 23, 37, 34, 17, 29 6. 9.3, 1.6, 8.2, 4.7, 8.9, 3, 11.4, 2.1, 1.6

find the mean, median, mode and range for each set of data. calculator usage is encouraged! 1. 23, 87, 19, 34, 37, 87, 81, 5, 14, 100, 26 2. 10, 11, 17, 14, 2, 13, 26 3. 86, 86, 24, 92, 37, 14, 52, 24, 63 4. 27, 54, 6, 31, 57, 22, 19, 12 5. 8, 32, 41, 6, 36, 10, 37, 31, 29, 37, 32, 11, 30, 15, 23, 37, 34, 17, 29 6. 9.3, 1.6, 8.2, 4.7, 8.9, 3, 11.4, 2.1, 1.6

Answer

1. For the data - set (23,87,19,34,37,87,81,5,14,100,26)

Explanation:

Step1: Calculate the mean

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $n = 11$ and $\sum_{i=1}^{11}x_{i}=23 + 87+19+34+37+87+81+5+14+100+26=513$. So, $\bar{x}=\frac{513}{11}\approx46.64$.

Step2: Find the median

First, arrange the data in ascending order: (5,14,19,23,26,34,37,81,87,87,100). Since (n = 11) (odd), the median is the (\left(\frac{n + 1}{2}\right))-th value. So, the median is the 6 - th value, which is (34).

Step3: Determine the mode

The mode is the value that appears most frequently. Here, (87) appears twice and other values appear once, so the mode is (87).

Step4: Calculate the range

The range is the difference between the maximum and minimum values. Range (=100 - 5=95).

2. For the data - set (10,11,17,14,2,13,26)

Explanation:

Step1: Calculate the mean

$n = 7$, $\sum_{i=1}^{7}x_{i}=10 + 11+17+14+2+13+26=93$. So, $\bar{x}=\frac{93}{7}\approx13.29$.

Step2: Find the median

Arrange the data in ascending order: (2,10,11,13,14,17,26). Since (n = 7) (odd), the median is the (\left(\frac{n+1}{2}\right))-th value, which is the 4 - th value, so the median is (13).

Step3: Determine the mode

Each value appears only once, so there is no mode.

Step4: Calculate the range

Range (=26 - 2=24).

3. For the data - set (86,86,24,92,37,14,52,24,63)

Explanation:

Step1: Calculate the mean

$n = 9$, $\sum_{i=1}^{9}x_{i}=86+86+24+92+37+14+52+24+63=478$. So, $\bar{x}=\frac{478}{9}\approx53.11$.

Step2: Find the median

Arrange the data in ascending order: (14,24,24,37,52,63,86,86,92). Since (n = 9) (odd), the median is the (\left(\frac{n + 1}{2}\right))-th value, which is the 5 - th value, so the median is (52).

Step3: Determine the mode

Both (24) and (86) appear twice, so the modes are (24) and (86).

Step4: Calculate the range

Range (=92 - 14=78).

4. For the data - set (27,54,6,31,57,22,19,12)

Explanation:

Step1: Calculate the mean

$n = 8$, $\sum_{i=1}^{8}x_{i}=27+54+6+31+57+22+19+12=228$. So, $\bar{x}=\frac{228}{8}=28.5$.

Step2: Find the median

Arrange the data in ascending order: (6,12,19,22,27,31,54,57). Since (n = 8) (even), the median is the average of the (\frac{n}{2})-th and (\left(\frac{n}{2}+1\right))-th values. The 4 - th and 5 - th values are (22) and (27), so the median is $\frac{22 + 27}{2}=24.5$.

Step3: Determine the mode

Each value appears only once, so there is no mode.

Step4: Calculate the range

Range (=57 - 6=51).

5. For the data - set (8,32,41,6,36,10,37,31,29,37,32,11,30,15,23,37,34,17,29)

Explanation:

Step1: Calculate the mean

$n = 19$, $\sum_{i=1}^{19}x_{i}=8+32+41+6+36+10+37+31+29+37+32+11+30+15+23+37+34+17+29=465$. So, $\bar{x}=\frac{465}{19}\approx24.47$.

Step2: Find the median

Arrange the data in ascending order: (6,8,10,11,15,17,23,29,29,30,31,32,32,34,36,37,37,37,41). Since (n = 19) (odd), the median is the (\left(\frac{n + 1}{2}\right))-th value, which is the 10 - th value, so the median is (30).

Step3: Determine the mode

The value (37) appears 3 times, more frequently than other values, so the mode is (37).

Step4: Calculate the range

Range (=41 - 6=35).

6. For the data - set (9.3,1.6,8.2,4.7,8.9,3,11.4,2.1,1.6)

Explanation:

Step1: Calculate the mean

$n = 9$, $\sum_{i=1}^{9}x_{i}=9.3+1.6+8.2+4.7+8.9+3+11.4+2.1+1.6=50.8$. So, $\bar{x}=\frac{50.8}{9}\approx5.64$.

Step2: Find the median

Arrange the data in ascending order: (1.6,1.6,2.1,3,4.7,8.2,8.9,9.3,11.4). Since (n = 9) (odd), the median is the (\left(\frac{n + 1}{2}\right))-th value, which is the 5 - th value, so the median is (4.7).

Step3: Determine the mode

The value (1.6) appears twice, so the mode is (1.6).

Step4: Calculate the range

Range (=11.4 - 1.6=9.8).

Answer:

  1. Mean: $\approx46.64$, Median: (34), Mode: (87), Range: (95)
  2. Mean: $\approx13.29$, Median: (13), Mode: None, Range: (24)
  3. Mean: $\approx53.11$, Median: (52), Modes: (24,86), Range: (78)
  4. Mean: (28.5), Median: (24.5), Mode: None, Range: (51)
  5. Mean: $\approx24.47$, Median: (30), Mode: (37), Range: (35)
  6. Mean: $\approx5.64$, Median: (4.7), Mode: (1.6), Range: (9.8)