3. find the missing values of the table. round to the nearest thousandth (3 decimal places)\nrental car…

3. find the missing values of the table. round to the nearest thousandth (3 decimal places)\nrental car prices for a family of 4 frequency relative frequency cumulative frequency relative cumulative frequency\n$478 2.074 2.074\n$570 3 a. 5.185\n$610 4.148 c. e.\n$675 6.223 15.556\n$705 4.148 19 f.\n$892 5 b. 24.889\n$1,094 3.111 d. 1
Answer
Explanation:
Step1: Calculate relative frequency for $570
Relative frequency = $\frac{\text{Frequency}}{\text{Total frequency}}$. First, find total frequency. From the first - row, if relative frequency of $478$ is $0.074$ and frequency is $2$, then total frequency $N=\frac{2}{0.074}\approx27$. For $570$ with frequency $3$, relative frequency $a = \frac{3}{27}\approx0.111$.
Step2: Calculate relative frequency for $892
For $892$ with frequency $5$, relative frequency $b=\frac{5}{27}\approx0.185$.
Step3: Calculate cumulative frequency for $610
Cumulative frequency for $610$ is the sum of frequencies of all previous values and the frequency of $610$ itself. Since previous cumulative frequency is $5$ and frequency of $610$ is $4$, $c = 5 + 4=9$.
Step4: Calculate cumulative frequency for $1094
Since the last relative cumulative frequency is $1$, the total cumulative frequency $d = 27$.
Step5: Calculate relative cumulative frequency for $610
Relative cumulative frequency for $610$ is the cumulative frequency of $610$ divided by total frequency. So $e=\frac{9}{27}=0.333$.
Step6: Calculate relative cumulative frequency for $705
Relative cumulative frequency for $705$ is $\frac{19}{27}\approx0.704$. So $f = 0.704$.
Answer:
a. $0.111$ b. $0.185$ c. $9$ d. $27$ e. $0.333$ f. $0.704$