find the residual values, and use the graphing calculator tool to make a residual plot.\n|x|given|predicted|r…
find the residual values, and use the graphing calculator tool to make a residual plot.\n|x|given|predicted|residual|\n|----|----|----|----|\n|1|-2.7|-2.84|\n|2|-0.9|-0.81|\n|3|1.1|1.22|\n|4|3.2|3.25|\n|5|5.4|5.28|\ndoes the residual plot show that the line of best fit is appropriate for the data?\nno, the points are in a curved pattern.\nno, the points are evenly distributed about the x - axis.\nyes, the points are in a linear pattern.\nyes, the points have no pattern.
Answer
Answer:
| x | Given | Predicted | Residual |
|---|---|---|---|
| 1 | -2.7 | -2.84 | -2.7 - (-2.84)=0.14 |
| 2 | -0.9 | -0.81 | -0.9 - (-0.81)= - 0.09 |
| 3 | 1.1 | 1.22 | 1.1 - 1.22=-0.12 |
| 4 | 3.2 | 3.25 | 3.2 - 3.25=-0.05 |
| 5 | 5.4 | 5.28 | 5.4 - 5.28 = 0.12 |
For the second - part: D. Yes, the points have no pattern.
Explanation:
Step1: Recall residual formula
Residual = Observed - Predicted
Step2: Calculate residual for x = 1
Residual = -2.7-(-2.84) = 0.14
Step3: Calculate residual for x = 2
Residual=-0.9 - (-0.81)=-0.09
Step4: Calculate residual for x = 3
Residual = 1.1 - 1.22=-0.12
Step5: Calculate residual for x = 4
Residual = 3.2 - 3.25=-0.05
Step6: Calculate residual for x = 5
Residual = 5.4 - 5.28 = 0.12
Step7: Analyze residual plot
A good residual plot for a well - fitting line of best fit has points randomly scattered (no pattern). So the answer is that the line of best fit is appropriate because the points have no pattern.