find the sum of the average monthly rainfalls. average monthly rainfall (inches)

Explanation:

Step1: Identify the values

Count the number of 'x's at each value on the number - line and note the corresponding rainfall value.

Step2: Calculate the sum of products

For $\frac{1}{8}$ inches, there are 3 'x's, so the contribution is $3\times\frac{1}{8}=\frac{3}{8}$. For $\frac{1}{4}$ inches, there are 2 'x's, so the contribution is $2\times\frac{1}{4}=\frac{1}{2}=\frac{4}{8}$. For $\frac{1}{2}$ inches, there is 1 'x', so the contribution is $\frac{1}{2}=\frac{4}{8}$. For $\frac{3}{4}$ inches, there is 1 'x', so the contribution is $\frac{3}{4}=\frac{6}{8}$. For 1 inch, there is 1 'x', so the contribution is 1=$\frac{8}{8}$. For $1\frac{1}{8}$ inches, there are 2 'x's, so the contribution is $2\times1\frac{1}{8}=2\times\frac{9}{8}=\frac{18}{8}$. For $1\frac{1}{4}$ inches, there are 2 'x's, so the contribution is $2\times1\frac{1}{4}=2\times\frac{5}{4}=\frac{10}{4}=\frac{20}{8}$. For $1\frac{3}{8}$ inches, there is 1 'x', so the contribution is $1\frac{3}{8}=\frac{11}{8}$. For $1\frac{1}{2}$ inches, there is 1 'x', so the contribution is $1\frac{1}{2}=\frac{3}{2}=\frac{12}{8}$. For $1\frac{5}{8}$ inches, there is 1 'x', so the contribution is $1\frac{5}{8}=\frac{13}{8}$. For $1\frac{7}{8}$ inches, there are 2 'x's, so the contribution is $2\times1\frac{7}{8}=2\times\frac{15}{8}=\frac{30}{8}$. For 2 inches, there are 2 'x's, so the contribution is $2\times2 = 4=\frac{32}{8}$.

Step3: Sum up all contributions

$\frac{3 + 4+4 + 6+8+18+20+11+12+13+30+32}{8}=\frac{161}{8}=20.125$

Answer:

$20.125$