finding the mean and median\nmiriams study group received test scores of 96, 81, 82, 99, 94, 92, 95, 82, and…

Explanation:

Step1: Calculate the mean

The mean formula is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points. Here, $n = 8$, and $\sum_{i=1}^{8}x_{i}=96 + 81+82 + 99+94+92+95+80=719$. So, $\bar{x}=\frac{719}{8}=89.875$.

Step2: Calculate the median

First, arrange the data in ascending order: $80,81,82,82,92,94,95,96,99$. Since $n = 8$ (an even number), the median formula is $M=\frac{x_{\frac{n}{2}}+x_{\frac{n}{2}+1}}{2}$. Here, $\frac{n}{2}=4$ and $\frac{n}{2}+1 = 5$. So, $x_{4}=82$ and $x_{5}=92$, and $M=\frac{82 + 92}{2}=87$.

Answer:

The mean is $89.875$. The median is $87$.