finding the mean and median using technology\nthe table shows the precipitation in december, in inches, for…

finding the mean and median using technology\nthe table shows the precipitation in december, in inches, for washington state from 2005 to 2013. what was the mean amount of precipitation during this time? round to the nearest hundredth.\nyear\tprecipitation\n2005\t5.98\n2006\t6.05\n2007\t7.59\n2008\t5.27\n2009\t3.11\n2010\t7.18\n2011\t2.95\n2012\t7.22\n2013\t2.61\n1.97 inches\n2.61 inches\n5.33 inches\n5.98 inches

finding the mean and median using technology\nthe table shows the precipitation in december, in inches, for washington state from 2005 to 2013. what was the mean amount of precipitation during this time? round to the nearest hundredth.\nyear\tprecipitation\n2005\t5.98\n2006\t6.05\n2007\t7.59\n2008\t5.27\n2009\t3.11\n2010\t7.18\n2011\t2.95\n2012\t7.22\n2013\t2.61\n1.97 inches\n2.61 inches\n5.33 inches\n5.98 inches

Answer

Explanation:

Step1: Sum up all precipitation values

$5.98 + 6.05+7.59 + 5.27+3.11+7.18+2.95+7.22+2.61=47.96$

Step2: Divide by number of years

There are 9 years from 2005 - 2013. So the mean is $\frac{47.96}{9}\approx5.33$

Answer:

5.33 inches