what is the first error she made in computing the variance?\nemi failed to find the difference of 89 - 78…
what is the first error she made in computing the variance?\nemi failed to find the difference of 89 - 78 correctly.\nemi divided by n - 1 instead of n.\nemi evaluated (46 - 78)^2 as -(32)^2.\nemi forgot to take the square root of - 135.6.
Answer
Explanation:
Step1: Analyze variance formula
The variance formula for a population is $\sigma^{2}=\frac{\sum_{i = 1}^{n}(x_{i}-\mu)^{2}}{n}$, where $x_{i}$ are data - points, $\mu$ is the mean and $n$ is the number of data - points. Here, $n = 5$.
Step2: Check calculation of $(46 - 78)^{2}$
We know that $(46-78)=- 32$, so $(46 - 78)^{2}=(-32)^{2}=1024$, not $-(32)^{2}=-1024$. Emi made an error in evaluating $(46 - 78)^{2}$ as $-(32)^{2}$.
Answer:
Emi evaluated $(46 - 78)^{2}$ as $-(32)^{2}$.