at the fisher farm, the weights of zucchini squash are normally distributed, with a mean of 5 ounces and a…

Answer:

C. 5.9 ounces

Explanation:

Step1: Find the z - score

We want the top 10% of the data. So the area to the left of the z - score is $1 - 0.10=0.90$. Looking up 0.90 in the z - table, the z - score is approximately $z = 1.28$.

Step2: Use the z - score formula

The z - score formula is $z=\frac{x-\mu}{\sigma}$, where $\mu$ is the mean, $\sigma$ is the standard deviation, and $x$ is the value we want to find. We know $\mu = 5$, $\sigma=0.7$, and $z = 1.28$. Rearranging the formula for $x$ gives $x=\mu+z\sigma$.

Step3: Calculate the value of x

Substitute the values into the formula: $x = 5+1.28\times0.7=5 + 0.896\approx5.9$ ounces.