a flight attendant looked over a list of recent passengers. the list contained passengers frequent flyer…

a flight attendant looked over a list of recent passengers. the list contained passengers frequent flyer status as well as the number of bags checked.\n| |0 checked bags|1 checked bag|\n|--|--|--|\n|bronze status|5|6|\n|silver status|4|4|\nwhat is the probability that a randomly selected passenger does not have silver status and does not have 1 checked bag?\nsimplify any fractions.

a flight attendant looked over a list of recent passengers. the list contained passengers frequent flyer status as well as the number of bags checked.\n| |0 checked bags|1 checked bag|\n|--|--|--|\n|bronze status|5|6|\n|silver status|4|4|\nwhat is the probability that a randomly selected passenger does not have silver status and does not have 1 checked bag?\nsimplify any fractions.

Answer

Explanation:

Step1: Calculate total number of passengers

Sum all values in the table: $5 + 6+4 + 4=19$.

Step2: Identify favorable cases

Passengers who do not have silver - status and do not have 1 checked bag are those with bronze status and 0 checked bags. There are 5 such passengers.

Step3: Calculate probability

Probability $P=\frac{\text{Number of favorable cases}}{\text{Total number of cases}}=\frac{5}{19}$.

Answer:

$\frac{5}{19}$