the following are beginning salaries for a certain industry in different areas: $56,250.00 $79,150.00…

Explanation:

Step1: Recall the mean formula

The mean $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$, where $x_{i}$ are the data - points and $n$ is the number of data - points. Here, $n = 9$, and the data set is $x_1 = 56250$, $x_2=79150$, $x_3 = 61360$, $x_4=57120$, $x_5 = 57120$, $x_6=57120$, $x_7=63190$, $x_8=65370$, $x_9=59160$.

Step2: Calculate the sum of the data - set

$\sum_{i = 1}^{9}x_{i}=56250 + 79150+61360+57120+57120+57120+63190+65370+59160=556840$.

Step3: Calculate the mean

$\bar{x}=\frac{556840}{9}\approx61871.11$. But it seems there is a mistake above, let's use the correct data from the multiple - choice options format. The data set is $56250,79150,61360,57120,57120,57120,63190,65370,59160$. Sum $S=56250 + 79150+61360+57120+57120+57120+63190+65370+59160 = 556840$. The mean $\bar{x}=\frac{556840}{9}\approx61871.11$. Re - checking with the data values in the question more carefully: The data set: $56250,79150,61360,57120,57120,57120,63190,65370,59160$ Sum $S = 56250+79150 + 61360+57120+57120+57120+63190+65370+59160=556840$ $\bar{x}=\frac{556840}{9}\approx61871.11$. But if we calculate with the correct values from the start: The data set: $56250,79150,61360,57120,57120,57120,63190,65370,59160$ Sum $S=56250+79150+61360+57120+57120+57120+63190+65370+59160 = 556840$ $\bar{x}=\frac{556840}{9}\approx61871.11$. Let's re - do the sum: $56250+79150+61360+57120+57120+57120+63190+65370+59160$ $=(56250)+(79150)+(61360)+3\times(57120)+(63190)+(65370)+(59160)$ $=56250+79150+61360 + 171360+63190+65370+59160$ $=(56250+79150)+61360+171360+(63190+65370)+59160$ $=135400+61360+171360+128560+59160$ $=(135400+61360)+171360+128560+59160$ $=196760+171360+128560+59160$ $=(196760+171360)+128560+59160$ $=368120+128560+59160$ $=(368120+128560)+59160$ $=496680+59160$ $=555840$ $\bar{x}=\frac{555840}{9}=61760$.

Answer:

$61760$