the following data represent the weights (in grams) of a simple random sample of a candy. 0.92 0.89 0.89…

the following data represent the weights (in grams) of a simple random sample of a candy. 0.92 0.89 0.89 0.92 0.92 0.87 0.92 0.86 0.80 0.90 determine the shape of the distribution of weights of the candies by drawing a frequency histogram and computing the mean and the median. which measure of central tendency best describes the weight of the candy? choose the correct frequency histogram below.

the following data represent the weights (in grams) of a simple random sample of a candy. 0.92 0.89 0.89 0.92 0.92 0.87 0.92 0.86 0.80 0.90 determine the shape of the distribution of weights of the candies by drawing a frequency histogram and computing the mean and the median. which measure of central tendency best describes the weight of the candy? choose the correct frequency histogram below.

Answer

Explanation:

Step1: Sort data

Sorted weights: 0.80, 0.86, 0.87, 0.89, 0.89, 0.90, 0.92, 0.92, 0.92, 0.92

Step2: Determine classes

Classes: [0.79,0.85), [0.85,0.91), [0.91,∞)

Step3: Count frequencies

Class1:1 (0.80), Class2:5 (0.86,0.87,0.89,0.89,0.90), Class3:4 (0.92×4)

Step4: Calculate mean

Mean = (0.80+0.86+0.87+0.89+0.89+0.90+0.92×4)/10 = 8.89/10 = 0.889

Step5: Calculate median

Median = (5th + 6th)/2 = (0.89 + 0.90)/2 = 0.895

Step6: Analyze shape

Mean ≈ median, distribution symmetric.

Answer:

The correct frequency histogram is the one with frequencies 1, 5, 4 for classes [0.79,0.85), [0.85,0.91), [0.91,∞). The mean is the best measure of central tendency.