the following list gives the number of pets for each of 15 students.\n0, 2, 2, 0, 2, 1, 2, 1, 4, 1, 1, 4, 0…

the following list gives the number of pets for each of 15 students.\n0, 2, 2, 0, 2, 1, 2, 1, 4, 1, 1, 4, 0, 3, 0\nfind the modes of this data set.\nif there is more than one mode, write them separated by commas.\nif there is no mode, click on \no mode.\
Answer
Answer:
0, 2
Explanation:
Step1: Count frequency of each value
0:4 times, 1:4 times, 2:4 times, 3:1 time, 4:1 time
Step2: Identify most frequent values
0,1,2 all appear 4 times (highest frequency)
Step3: Confirm modes
Multiple modes: 0,2,1? Wait correction: recount data: 0,2,2,0,2,1,2,1,4,1,1,0,3,0 → let's list all 15: positions 1-15: 1(0),2(2),3(2),4(0),5(2),6(1),7(2),8(1),9(4),10(1),11(1),12(0),13(3),14(0) → wait 14 values? Wait original data: "0,2,2,0,2,1,2,1,4,1,1,0,3,0" is 14, but problem says 15. Assume typo but existing data: 0: positions1,4,12,14 →4; 2:2,3,5,7→4;1:6,8,10,11→4; 3:13→1;4:9→1. So 0,1,2 each 4 times. But if we take given data as is, modes are 0,1,2. Wait maybe I miscounted: let's do again carefully:
Data set: 0, 2, 2, 0, 2, 1, 2, 1, 4, 1, 1, 0, 3, 0 → count each number:
- 0: let's see how many times it appears: 1st element (0), 4th (0), 12th (0),14th(0) → 4 times
- 2: 2nd,3rd,5th,7th → 4 times -1:6th,8th,10th,11th →4 times -3:13th→1 -4:9th→1
So all three (0,1,2) have same highest frequency. So modes are 0,1,2. But maybe the problem had a typo. Alternatively, if the user's data is correct as written (even if 14 elements), the modes are 0,1,2. But let's check again:
Wait the user wrote: "0,2,2,0,2,1,2,1,4,1,1,0,3,0" → yes 14 numbers. But regardless, the most frequent are 0,1,2 each with 4 occurrences. So the modes are 0,1,2.
Wait correction final: the modes are 0,1,2. Because they all occur 4 times which is the highest frequency. So answer is 0,1,2.
Answer:
0,1,2
Explanation:
Step1: Count each value's occurrences
0:4, 1:4,2:4,3:1,4:1
Step2: Find values with max frequency
0,1,2 (max frequency=4)
Step3: State modes
0,1,2