what is the formula for margin of error?\n \text{me}=\frac{zcdotsqrt{s}}{sqrt{n}} \n \text{me}=\frac{zcdotsqr…

Brief Explanations:

The margin - of - error formula for a confidence interval when the population standard deviation $\sigma$ is unknown (and we use the sample standard deviation $s$ instead) for a large sample or a normal population is $ME = \frac{z\cdot s}{\sqrt{n}}$, where $z$ is the z - score corresponding to the desired confidence level, $s$ is the sample standard deviation, and $n$ is the sample size.

Answer:

C. $ME=\frac{z\cdot s}{\sqrt{n}}$