four girls and six boys are in a spanish club. three of the people will be chosen at random to represent the…

four girls and six boys are in a spanish club. three of the people will be chosen at random to represent the group in a photograph. what is the probability that one girl and two boys will be chosen? 40% 50% 60% 70%

four girls and six boys are in a spanish club. three of the people will be chosen at random to represent the group in a photograph. what is the probability that one girl and two boys will be chosen? 40% 50% 60% 70%

Answer

Explanation:

Step1: Calculate total number of people

There are 4 girls and 6 boys, so $4 + 6=10$ people in total.

Step2: Calculate total number of ways to choose 3 people

Using combination formula $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n = 10$ and $r = 3$. So $C(10,3)=\frac{10!}{3!(10 - 3)!}=\frac{10\times9\times8}{3\times2\times1}=120$.

Step3: Calculate number of ways to choose 1 girl and 2 boys

Number of ways to choose 1 girl out of 4 is $C(4,1)=\frac{4!}{1!(4 - 1)!}=4$. Number of ways to choose 2 boys out of 6 is $C(6,2)=\frac{6!}{2!(6 - 2)!}=\frac{6\times5}{2\times1}=15$. By multiplication - principle, number of ways to choose 1 girl and 2 boys is $C(4,1)\times C(6,2)=4\times15 = 60$.

Step4: Calculate the probability

Probability $P=\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}=\frac{60}{120}=0.5 = 50%$.

Answer:

50%