four seniors and six juniors are competing for four places on a quiz bowl team. what is the approximate…

four seniors and six juniors are competing for four places on a quiz bowl team. what is the approximate probability that all four seniors will be chosen at random? 0.00020 0.00476 0.06667 0.07142
Answer
Explanation:
Step1: Calculate total number of students
There are 4 seniors and 6 juniors, so the total number of students is $4 + 6=10$.
Step2: Calculate number of ways to choose 4 students out of 10
We use the combination formula $C(n,r)=\frac{n!}{r!(n - r)!}$, where $n = 10$ and $r = 4$. So $C(10,4)=\frac{10!}{4!(10 - 4)!}=\frac{10\times9\times8\times7}{4\times3\times2\times1}=210$.
Step3: Calculate number of ways to choose 4 seniors out of 4
Using the combination formula with $n = 4$ and $r = 4$, $C(4,4)=\frac{4!}{4!(4 - 4)!}=1$.
Step4: Calculate the probability
The probability $P$ that all four - seniors are chosen is the number of favorable outcomes (choosing 4 seniors) divided by the number of total outcomes (choosing 4 students out of 10). So $P=\frac{C(4,4)}{C(10,4)}=\frac{1}{210}\approx0.00476$.
Answer:
0.00476