fredrick hit 14, 18, 13, 12, 12, 16, 13, 12, 1, and 15 home runs in 10 seasons of play. which statements are…

fredrick hit 14, 18, 13, 12, 12, 16, 13, 12, 1, and 15 home runs in 10 seasons of play. which statements are correct? check all that apply. fredricks data set contains an outlier. the median value is 12 home runs. the mean value is about 12.6 home runs. the median describes fredricks data more accurately than the mean. the mean value stays the same when the outlier is not included in the data set.

fredrick hit 14, 18, 13, 12, 12, 16, 13, 12, 1, and 15 home runs in 10 seasons of play. which statements are correct? check all that apply. fredricks data set contains an outlier. the median value is 12 home runs. the mean value is about 12.6 home runs. the median describes fredricks data more accurately than the mean. the mean value stays the same when the outlier is not included in the data set.

Answer

Explanation:

Step1: Arrange data in ascending order

1, 12, 12, 12, 13, 13, 14, 15, 16, 18

Step2: Check for outlier

The value 1 is far - from other values, so there is an outlier.

Step3: Calculate median

There are 10 data points. Median is the average of 5th and 6th ordered values. $\frac{13 + 13}{2}=13$.

Step4: Calculate mean

$\text{Mean}=\frac{1+12 + 12+12+13+13+14+15+16+18}{10}=\frac{126}{10} = 12.6$

Step5: Analyze median and mean

Due to the outlier 1, the mean is pulled down. The median (13) is a better representation of the typical number of home - runs.

Step6: Calculate mean without outlier

$\text{Mean}=\frac{12 + 12+12+13+13+14+15+16+18}{9}=\frac{125}{9}\approx13.9$, the mean changes.

Answer:

Fredrick's data set contains an outlier. The mean value is about 12.6 home runs. The median describes Fredrick's data more accurately than the mean.