a fruit is randomly drawn from a basket with 20 red apples, 6 green apples, 14 green pears, and 10 yellow…

a fruit is randomly drawn from a basket with 20 red apples, 6 green apples, 14 green pears, and 10 yellow pears. event a: green event b: pear p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.
Answer
Explanation:
Step1: Calculate total number of fruits
$20 + 6+14 + 10=50$
Step2: Calculate P(A)
$P(A)=\frac{6 + 14}{50}=\frac{20}{50}=0.4$
Step3: Calculate P(B)
$P(B)=\frac{14 + 10}{50}=\frac{24}{50}=0.48$
Step4: Calculate P(A and B)
$P(A\text{ and }B)=\frac{14}{50}=0.28$
Step5: Calculate P(A or B)
$P(A\text{ or }B)=P(A)+P(B)-P(A\text{ and }B)=0.4 + 0.48- 0.28=0.6$
Answer:
$0.60$