a fruit is randomly drawn from a basket with 20 red apples, 6 green apples, 14 green pears, and 10 yellow…

a fruit is randomly drawn from a basket with 20 red apples, 6 green apples, 14 green pears, and 10 yellow pears. event a: green event b: apple p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.

a fruit is randomly drawn from a basket with 20 red apples, 6 green apples, 14 green pears, and 10 yellow pears. event a: green event b: apple p(a or b) = ? hint: p(a or b) = p(a) + p(b) - p(a and b) round your answer to the nearest hundredth.

Answer

Explanation:

Step1: Calculate total number of fruits

$20 + 6+14 + 10=50$

Step2: Calculate P(A)

Number of green fruits is $6 + 14=20$. So $P(A)=\frac{20}{50}$

Step3: Calculate P(B)

Number of apples is $20 + 6 = 26$. So $P(B)=\frac{26}{50}$

Step4: Calculate P(A and B)

Number of green - apples is 6. So $P(A\ and\ B)=\frac{6}{50}$

Step5: Calculate P(A or B)

Using the formula $P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$, we have $P(A\ or\ B)=\frac{20}{50}+\frac{26}{50}-\frac{6}{50}=\frac{20 + 26-6}{50}=\frac{40}{50}=0.80$

Answer:

$0.80$