garrett wanted to know if there was a connection between his coffee consumption and how well he slept that…

garrett wanted to know if there was a connection between his coffee consumption and how well he slept that night. for weeks, garrett recorded how many cups of coffee he drank in the morning and how many hours he slept that night. 6 hours 7 hours 0 cups of coffee 7 10 1 cup of coffee 8 6 2 cups of coffee 5 13 what is the probability that a randomly selected day is one when he drank exactly 1 cup of coffee or 0 cups of coffee? simplify any fractions.

garrett wanted to know if there was a connection between his coffee consumption and how well he slept that night. for weeks, garrett recorded how many cups of coffee he drank in the morning and how many hours he slept that night. 6 hours 7 hours 0 cups of coffee 7 10 1 cup of coffee 8 6 2 cups of coffee 5 13 what is the probability that a randomly selected day is one when he drank exactly 1 cup of coffee or 0 cups of coffee? simplify any fractions.

Answer

Explanation:

Step1: Calculate total number of days

Add up all the values in the table: $7 + 10+8 + 6+5 + 13=49$.

Step2: Calculate number of days with 0 or 1 cup of coffee

Add the values for 0 - cup and 1 - cup rows: $(7 + 10)+(8 + 6)=31$.

Step3: Calculate the probability

The probability $P$ is the number of favorable outcomes (days with 0 or 1 cup) divided by the total number of outcomes (total days). So $P=\frac{31}{49}$.

Answer:

$\frac{31}{49}$