garrett wanted to know if there was a connection between his coffee consumption and how well he slept that…

garrett wanted to know if there was a connection between his coffee consumption and how well he slept that night. for weeks, garrett recorded how many cups of coffee he drank in the morning and how many hours he slept that night.\n\n| |6 hours|7 hours|\n|--|--|--|\n|0 cups of coffee|7|10|\n|1 cup of coffee|8|6|\n|2 cups of coffee|5|13|\n\nwhat is the probability that a randomly selected day is one when he drank exactly 1 cup of coffee or 0 cups of coffee?\n\nsimplify any fractions.

garrett wanted to know if there was a connection between his coffee consumption and how well he slept that night. for weeks, garrett recorded how many cups of coffee he drank in the morning and how many hours he slept that night.\n\n| |6 hours|7 hours|\n|--|--|--|\n|0 cups of coffee|7|10|\n|1 cup of coffee|8|6|\n|2 cups of coffee|5|13|\n\nwhat is the probability that a randomly selected day is one when he drank exactly 1 cup of coffee or 0 cups of coffee?\n\nsimplify any fractions.

Answer

Answer:

$\frac{31}{49}$

Explanation:

Step1: Calculate total number of days

$7 + 10+8 + 6+5 + 13=49$

Step2: Calculate number of days with 0 or 1 cup of coffee

$(7 + 10)+(8 + 6)=31$

Step3: Calculate probability

The probability $P=\frac{31}{49}$