given that the variance of life expectancies was 83.06 squared years, which of the following is the correct…
given that the variance of life expectancies was 83.06 squared years, which of the following is the correct standard deviation and units?\n√83.06 = 9.1 squared years\n√83.06 = 9.1 years\n83.06² = 6899 years\n83.06² = 6899 squared years\n83.06/(201 - 1)=0.4153 years
Answer
Explanation:
Step1: Recall standard - deviation formula
The standard deviation $\sigma$ is the square - root of the variance $\sigma^{2}$. That is, $\sigma=\sqrt{\sigma^{2}}$.
Step2: Calculate standard deviation
Given $\sigma^{2} = 83.06$ squared years, then $\sigma=\sqrt{83.06}\approx9.1$ years. The units of variance are squared units of the original variable, and the units of standard deviation are the same as the original variable (years in this case for life - expectancies).
Answer:
$\sqrt{83.06}=9.1$ years