gracie loves to talk on the phone, but her parents try to limit the amount of time she talks. they decided…

gracie loves to talk on the phone, but her parents try to limit the amount of time she talks. they decided to keep a record of the number or minutes that she spends on the phone each day. here are the data for the past nine days: 120, 60, 0, 30, 15, 0, 0, 10, and 20.\na) find the mean and median for the information.\nb) which of the two measures in part (a) would give gracie’s parent the most accurate information about her phone use? why do you think so?

gracie loves to talk on the phone, but her parents try to limit the amount of time she talks. they decided to keep a record of the number or minutes that she spends on the phone each day. here are the data for the past nine days: 120, 60, 0, 30, 15, 0, 0, 10, and 20.\na) find the mean and median for the information.\nb) which of the two measures in part (a) would give gracie’s parent the most accurate information about her phone use? why do you think so?

Answer

Explanation:

Step1: Calculate the mean

The mean formula is $\bar{x}=\frac{\sum_{i = 1}^{n}x_{i}}{n}$. Here $x_{i}$ are the data - points $120,60,0,30,15,0,0,10,20$ and $n = 9$. $\sum_{i=1}^{9}x_{i}=120 + 60+0 + 30+15+0+0+10+20=255$. $\bar{x}=\frac{255}{9}=\frac{85}{3}\approx28.33$.

Step2: Calculate the median

First, order the data: $0,0,0,10,15,20,30,60,120$. Since $n = 9$ (an odd number), the median is the $\left(\frac{n + 1}{2}\right)$-th value. $\frac{9+1}{2}=5$-th value. So the median is $15$.

Step3: Analyze which measure is more accurate

The mean is affected by the out - lier value of $120$. The median is not affected by extreme values. In this case, the median gives a more typical value of the daily phone - use time as most of the values are in the lower range and the high value of $120$ skews the mean.

Answer:

a) Mean: $\frac{85}{3}\approx28.33$, Median: $15$ b) The median gives the most accurate information about her phone use because the mean is skewed by the outlier value of $120$.