the graph below displays the cost of a gym membership with additional classes. if x represents the number of…
the graph below displays the cost of a gym membership with additional classes. if x represents the number of classes and y is the total membership monthly cost, how many classes can a person take to keep the cost at or below $30 a month?
Answer
Explanation:
Step1: Identify the line equation
Assume the linear equation is ( y = mx + b ). From the graph, when ( y = 30 ), we find the corresponding ( x )-value. By visually inspecting the grid, the line passes through a point where ( y = 30 ) and ( x = 10 ) (assuming grid intervals are consistent, e.g., each square is 1 unit for ( x ) and ( y ) in terms of the problem's context). Wait, actually, let's check the slope. Wait, maybe the graph has a y-intercept (base cost) and slope (cost per class). But since we need ( y \leq 30 ), we find the ( x ) when ( y = 30 ). From the graph, the line at ( y = 30 ) intersects ( x = 10 ) (assuming the grid: let's say each horizontal line is 5 units? Wait no, the y-axis has 20 and 30. Wait, maybe the x-axis is number of classes, y-axis is cost. Let's see, when y=30, the x-coordinate is 10? Wait, maybe the line is ( y = 2x + 10 )? No, better to look at the graph: when y=30, x=10 (since the line reaches y=30 at x=10). So to keep y ≤30, x ≤10.
Step2: Confirm the intersection
Looking at the graph, the line (representing total cost) crosses the horizontal line ( y = 30 ) at ( x = 10 ). So for ( y \leq 30 ), ( x ) (number of classes) must be at most 10.
Answer:
10