the graph shows the ages of different concert - goers who have back - stage passes. which statement is true…

the graph shows the ages of different concert - goers who have back - stage passes. which statement is true about the graph? a late arrival who is 21 years old with a back - stage pass will make the mean greater than the median. the two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age. the ages of concert - goers with back - stage passes are skewed left, so the mean age is less than the median age. a concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.
Answer
Answer:
A concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.
Explanation:
Step1: Recall mean and median concepts
Mean is the average value, median is the middle value.
Step2: Analyze effect of new data point
An 18 - year - old is a relatively low value. In a distribution like this, a low value will affect the mean more than the median. Since the mean is more sensitive to extreme values, adding an 18 - year - old will decrease the mean more significantly than it will decrease the median. So it is likely to pull the mean more than 2 years less than the median.
Step3: Analyze other options
- A late - arrival 21 - year - old won't make mean > median as 21 is around the middle of the distribution.
- Holders above 40 won't necessarily make mean > median as their number is small compared to the whole.
- The distribution is not clearly skewed left.