the graph shows the ages of different concertgoers who have backstage passes. which statement is true about…

the graph shows the ages of different concertgoers who have backstage passes. which statement is true about the graph? a late arrival who is 21 years old with a back - stage pass will make the mean greater than the median. the two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age. the ages of concert - goers with backstage passes are skewed left, so the mean age is less than the median age. a concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.

the graph shows the ages of different concertgoers who have backstage passes. which statement is true about the graph? a late arrival who is 21 years old with a back - stage pass will make the mean greater than the median. the two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age. the ages of concert - goers with backstage passes are skewed left, so the mean age is less than the median age. a concert - goer who is 18 years old and wins a back - stage pass will pull the mean more than 2 years less than the median.

Answer

Answer:

B. The two holders of back - stage passes whose ages are above 40 make the mean age higher than the median age.

Explanation:

Step1: Comprendre la distribution

La distribution semble avoir des valeurs extrêmes (âges au - delà de 40).

Step2: Comprendre l'effet sur la moyenne et la médiane

Les valeurs extrêmes (en général, les valeurs élevées ici) poussent la moyenne vers le haut, tandis que la médiane est moins affectée par les valeurs extrêmes. Donc, les deux personnes avec des âges au - delà de 40 feront augmenter la moyenne plus que la médiane.