hector, a soup chef at a new restaurant, kept track of the first days soup sales.\n| | split pea | chicken…

hector, a soup chef at a new restaurant, kept track of the first days soup sales.\n| | split pea | chicken noodle |\n|--|--|--| \n| cup | 5 | 6 |\n| bowl | 6 | 3 |\nwhat is the probability that a randomly selected soup was not ordered in a bowl and was not split pea?\nsimplify any fractions.

hector, a soup chef at a new restaurant, kept track of the first days soup sales.\n| | split pea | chicken noodle |\n|--|--|--| \n| cup | 5 | 6 |\n| bowl | 6 | 3 |\nwhat is the probability that a randomly selected soup was not ordered in a bowl and was not split pea?\nsimplify any fractions.

Answer

Explanation:

Step1: Calculate total number of soups

$5 + 6+6 + 3=20$

Step2: Identify favorable cases

The soups that are not in a bowl and not split - pea are chicken noodle cups. There are 6 chicken noodle cups.

Step3: Calculate probability

The probability $P$ is the number of favorable cases divided by the total number of cases. So $P=\frac{6}{20}=\frac{3}{10}$

Answer:

$\frac{3}{10}$