hector surveyed students in his homeroom about how they got to school last monday and noted whether they…

hector surveyed students in his homeroom about how they got to school last monday and noted whether they arrive on time or late. the data he gathered is shown in the two - way table below.\nstudent arrivals to school last monday\n| |arrive on time|arrive late|\n|--|--|--|\n|take bus|10|3|\n|do not take bus|8|4|\naccording to the data in the table, what percentage of students in hectors homeroom did not take the bus to school last monday?\n%

hector surveyed students in his homeroom about how they got to school last monday and noted whether they arrive on time or late. the data he gathered is shown in the two - way table below.\nstudent arrivals to school last monday\n| |arrive on time|arrive late|\n|--|--|--|\n|take bus|10|3|\n|do not take bus|8|4|\naccording to the data in the table, what percentage of students in hectors homeroom did not take the bus to school last monday?\n%

Answer

Explanation:

Step1: Calculate total students

First, find the total number of students who did not take the bus. Add the number of on - time and late arrivals for non - bus takers: $8 + 4=12$. Then find the total number of students in the homeroom. The total number of students who took the bus is $10 + 3 = 13$, and the total number of students who did not take the bus is $8+4 = 12$. So the total number of students in the homeroom is $13+12=25$.

Step2: Calculate the percentage

Use the formula for percentage: $\text{Percentage}=\frac{\text{Number of non - bus takers}}{\text{Total number of students}}\times100%$. Substitute the values: $\frac{12}{25}\times100%$. Since $\frac{12}{25}=0.48$, then $0.48\times100% = 48%$.

Answer:

48%