what would the height need to be for this curve to be a density curve?\n-\\frac{1}{6}\n\\frac{1}{6}\n\\frac{1…

what would the height need to be for this curve to be a density curve?\n-\\frac{1}{6}\n\\frac{1}{6}\n\\frac{1}{5}\n1

what would the height need to be for this curve to be a density curve?\n-\\frac{1}{6}\n\\frac{1}{6}\n\\frac{1}{5}\n1

Answer

Explanation:

Step1: Recall the property of a density curve

The area under a density curve is (1). For a rectangular density curve, the area (A = \text{base}\times\text{height}).

Step2: Calculate the base length

The base length (b) of the rectangle is (1-(- 5)=6). Let the height be (h). Using the formula (A = b\times h), and since (A = 1), we have (1=6\times h).

Step3: Solve for (h)

From (1 = 6h), we can solve for (h) by dividing both sides of the equation by (6). So (h=\frac{1}{6}).

Answer:

(\frac{1}{6}) (the second option)