the heights (in centimeters) of 9 students are listed in the box. 136, 140, 125, 120, 132, 145, 112, 116…

Explanation:

Step1: Arrange data in ascending order

$105, 112, 116, 120, 125, 132, 136, 140, 145$

Step2: Find the median (Q2)

Since $n = 9$ (odd), median is the $\left(\frac{n + 1}{2}\right)$-th value. $\frac{9+1}{2}=5$ - th value, so $Q2=125$

Step3: Find the lower - half data

The lower - half data is $105, 112, 116, 120$.

Step4: Find Q1

Since $n = 4$ (even) for lower - half data, $Q1=\frac{112 + 116}{2}=114$

Step5: Find the upper - half data

The upper - half data is $132, 136, 140, 145$.

Step6: Find Q3

Since $n = 4$ (even) for upper - half data, $Q3=\frac{136+140}{2}=138$

Step7: Identify the minimum and maximum

The minimum value is $105$ and the maximum value is $145$

We look for a box - plot with minimum at $105$, $Q1$ at $114$, median at $125$, $Q3$ at $138$ and maximum at $145$.

Answer:

(You need to visually check the box - plots provided in the original image to select the correct one based on the calculated values of minimum, Q1, median, Q3 and maximum. Without the ability to directly view the visual options, I can't specify which one it is from the list, but you can use the values $105,114,125,138,145$ to make the selection.)